c语言100以内加减乘除,一百以内的加减乘除法游戏....

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#include

void main()

{

int n,i,m,time1=0;long answer1,answer;float a[10]; char c[2],str[10];

long result(float a[],char str[],int n);

begin:

time1=0;

srand(time(NULL));

n=(rand()%10)+3;

if(n/2)

n=n+1;

for(i=0;i

a[i]=rand()%300+1;

m=rand()%4;

switch(m)

case 0:str[i]='+';break;

case 1:str[i]='-';break;

case 2:str[i]='*';break;

case 3:str[i]='/';break;

}

printf("this is a text please show right answer you have 3 times GOOD LUCK ");

printf("%.2f%c",a[i],str[i]);

printf("%.2f",a[(n+1)/2-1]);

printf(" ");

printf("input your answer ");

answer=result(a,str,n);

do

scanf("%ld",&answer1);

getchar();

time1++;

}while(answer1!=answer&&time1<=3);

if(answer==answer1)

printf("you are right ");

if(answer!=answer1)

printf("sorry the right answer is %ld ",answer);

printf("try again?Y/N ");

scanf("%s",c);

if(c[0]=='y'||c[0]=='Y')

goto begin;

long result(float a[],char str[],int n)

int i,j,a1,b;

a1=(n-1)/2;

b=(n+1)/2;

if(str[i]=='*')

a[i]=a[i]*a[i+1];

a1--;b--;

for(j=i;j

str[j]=str[j+1];

for(j=i+1;j

a[j]=a[j+1];

i--;

if(str[i]=='/')

a[i]=a[i]/a[i+1];

if(str[i]=='+')

a[i]=a[i]+a[i+1];

if(str[i]=='-')

a[i]=a[i]-a[i+1];

return((long)a[0]);

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